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3x^2+21x-180=0
a = 3; b = 21; c = -180;
Δ = b2-4ac
Δ = 212-4·3·(-180)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-51}{2*3}=\frac{-72}{6} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+51}{2*3}=\frac{30}{6} =5 $
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